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x^2+x+x^2+4=360
We move all terms to the left:
x^2+x+x^2+4-(360)=0
We add all the numbers together, and all the variables
2x^2+x-356=0
a = 2; b = 1; c = -356;
Δ = b2-4ac
Δ = 12-4·2·(-356)
Δ = 2849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2849}}{2*2}=\frac{-1-\sqrt{2849}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2849}}{2*2}=\frac{-1+\sqrt{2849}}{4} $
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